(2x-3)*(x^2-5x+2)=0

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Solution for (2x-3)*(x^2-5x+2)=0 equation: 


Simplifying
(2x + -3)(x2 + -5x + 2) = 0

Reorder the terms:
(-3 + 2x)(x2 + -5x + 2) = 0

Reorder the terms:
(-3 + 2x)(2 + -5x + x2) = 0

Multiply (-3 + 2x) * (2 + -5x + x2)
(-3(2 + -5x + x2) + 2x * (2 + -5x + x2)) = 0
((2 * -3 + -5x * -3 + x2 * -3) + 2x * (2 + -5x + x2)) = 0
((-6 + 15x + -3x2) + 2x * (2 + -5x + x2)) = 0
(-6 + 15x + -3x2 + (2 * 2x + -5x * 2x + x2 * 2x)) = 0
(-6 + 15x + -3x2 + (4x + -10x2 + 2x3)) = 0

Reorder the terms:
(-6 + 15x + 4x + -3x2 + -10x2 + 2x3) = 0

Combine like terms: 15x + 4x = 19x
(-6 + 19x + -3x2 + -10x2 + 2x3) = 0

Combine like terms: -3x2 + -10x2 = -13x2
(-6 + 19x + -13x2 + 2x3) = 0

Solving
-6 + 19x + -13x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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